[求助]救命啊~~救命~~

.:〖综合技术讨论区〗:. 程序设计
1

我们现在正在考试汇编只考了一题~…注:重修…
请各位 大哥 大姐 帮忙救救我们~…
题目是 第一项为1 第二项 为1 第 3 项 为前两项 之和
例如 1 1 2 3 5 8 13 21 34 55
就是这样…用汇编编出来…
谢谢啊~~

2

代码初稿仅供参考，只显示小于1000的数值，结果如下：
1 1 2 3 5 8 13 21 34 55 89 144 233 377 610 987

代码如下：

DSEG SEGMENT ‘DATA’

DSEG ENDS

SSEG SEGMENT STACK ‘STACK’
DW 100h DUP(?)
SSEG ENDS

CSEG SEGMENT ‘CODE’

;*******************************************
ASSUME CS:CSEG,DS:DSEG,ES:DSEG,SS:SSEG

START PROC FAR

; Store return address to OS:
PUSH DS
MOV AX, 0
PUSH AX

; set segment registers:
MOV AX, DSEG
MOV DS, AX
MOV ES, AX

init:
mov si,1
mov di,0

first:
add si,di
mov ax,si
cmp ax,1000d ;if(ax>=1000d)jmp exit
jge exit
call bindec

next:
add di,si
mov ax,di
cmp ax,1000d ;if(ax>=1000d)jmp exit
jge exit
call bindec

    jmp first

;return to operating system:
exit:
RET
START ENDP

;subroutine to convert binary in AX to decimal
bindec proc near

cmp ax,100d
jl m_10d

m_100d: mov cx,100d
call decdiv

m_10d: cmp ax,10d
jl m_1d
mov cx,10d
call decdiv

m_1d: mov cx,1
call decdiv

blank:
xor al,al
mov al,20h ;add a space key
call printf

ret

bindec endp

;subroutine to divide number in AX by CX
decdiv proc near
mov dx,0
div cx
add al,30h ;convert to ASCII
call printf
mov ax,dx
ret
decdiv endp

;subroutine to printf
printf proc near
mov bx,0
mov ah,0eh ;display function
int 10h
ret
printf endp
;*******************************************

CSEG ENDS

    END    START    ; set entry point.